Question 200: Motion in 2D & Vectors

Question

For angles of projection of a projectile at angle (45
o
$$-$$ $$	heta $$) and (45
o
+ $$	heta $$), the horizontal range described by the projectile are in the ratio of

Accepted Answer

(45ÃÂº Ã¢ÂÂ $$	heta $$) & (45ÃÂº + $$	heta $$) are complementary
angles as 45ÃÂº Ã¢ÂÂ $$	heta $$ + 45ÃÂº + $$	heta $$ = 90ÃÂº. We know that if
angle of projection of two projectiles make
complementary angles, their ranges are equal.
In this case also, the range will be same. So the
ratio is 1 : 1.

Answer

2 : 1

Answer

1 : 1

Answer

2 : 3

Answer

1 : 2.

Motion in 2D & Vectors

For angles of projection of a projectile at angle (45 o $- \theta ) and (45 o + \theta $), the horizontal range described by the projectile are in the ratio of

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