Question 141: Motion in 2D & Vectors

Question

A projectile can have the same range 'R' for two angles of projection. If T
1
and T
2
be the time
of flights in the two cases, then the product of the two time of flights is directly proportional to

Accepted Answer

Range is same for angle of projection $$	heta ,$$ and $${90^ \circ } - 	heta $$
$${T_1} = {{2u\sin 	heta } \over g},\,\,{T_2} = {{2u\cos 	heta } \over g}$$
$${T_1}{T_2} =$$ $${{4{u^2}\sin 	heta \cos 	heta } \over {{g^2}}}$$
= $${2 \over g} 	imes \left( {{{{u^2}\sin 2	heta } \over g}} ight)$$
= $${{2R} \over g}$$
(as $$R = $$$${{{{u^2}\sin 2	heta } \over g}}$$ )
Hence, $${T_1}{T_2}$$ is proportional to $$R.$$

Answer

R

Answer

$${1 \over R}$$

Answer

$${1 \over {{R^2}}}$$

Answer

$${R^2}$$

Motion in 2D & Vectors

A projectile can have the same range 'R' for two angles of projection. If T 1 and T 2 be the time of flights in the two cases, then the product of the two time of flights is directly proportional to

Choose the correct answer: