Question 64: Motion in 1D

Question

A scooter accelerates from rest for time t
1
at constant rate a
1
and then retards at constant rate a
2
for time t
2
and comes to rest. The correct value of $${{{t_1}} \over {{t_2}}}$$ wil be :

Accepted Answer

From given information :
For 1
st
interval
$${a_1} = {{{v_0}} \over {{t_1}}}$$
v
0
= a
1
t
1
....... (1)
For 2
nd
interval
$${a_2} = {{{v_0}} \over {{t_2}}}$$
v
0
= a
2
t
2
..... (2)
from (1) & (2)
a
1
t
1
= a
2
t
2
$${{{t_1}} \over {{t_2}}} = {{{a_2}} \over {{a_1}}}$$

Answer

$${{{a_1} + {a_2}} \over {{a_2}}}$$

Answer

$${{{a_1} + {a_2}} \over {{a_1}}}$$

Answer

$${{{a_2}} \over {{a_1}}}$$

Answer

$${{{a_1}} \over {{a_2}}}$$

Motion in 1D

A scooter accelerates from rest for time t 1 at constant rate a 1 and then retards at constant rate a 2 for time t 2 and comes to rest. The correct value of ${{{t_1}} \over {{t_2}}}$ wil be :

Choose the correct answer: