Question 40: Motion in 1D

Question

The velocity time graph of a body moving in a straight line is shown in the figure.
The ratio of displacement to distance travelled by the body in time 0 to 10s is :
![](https://app-content.cdn.examgoal.net/fly/@width/image/1lesvstw5/3c8e1940-d40f-474a-bf3c-d2d478ef0494/f4328850-b9f2-11ed-89b5-a150a08c777c/file-1lesvstw6.png?format=png)

Accepted Answer

From $v$-t graph
Displacement $=$ Area under curve considering sign also.
Distance $=$ Area under curve considering only magnitude
Displacement $= \Sigma$area $=8$ 	imes $2-4$ 	imes $2+4$ 	imes $4-2$ 	imes $4=16 \mathrm{~m}$
Distance $=\Sigma \mid$ area $\mid=48 \mathrm{~m}$
Displacement : distance $=1: 3$

Answer

1 : 1

Answer

1 : 3

Answer

1 : 4

Answer

1 : 2

Motion in 1D

The velocity time graph of a body moving in a straight line is shown in the figure. The ratio of displacement to distance travelled by the body in time 0 to 10s is :

Choose the correct answer: