Question 146: Motion in 1D

Question

The motion of a particle along a straight line is described by equation x = 8 + 12t $-$ t
3
where x is in metre and t in second. The retardation of the particle when its velocity  becomes zero is

Accepted Answer

Given x = 8 + 12t $-$ t
3
Velocity, v = ${{dx} \over {dt}}$ = 12 - 3t
2
When  v = 0, then 12 - 3t
2
= 0
$ \Rightarrow $ t = 2 s
$a = {{dv} \over {dt}}$ = - 6t
$ 	herefore $ At t = 2 s, $a$ = - 12 m/s
2
$ 	herefore $ Retardation = 12 m/s
2

Answer

24 m s
$-$2

Answer

zero

Answer

6 m s
$-$2

Answer

12 m s
$-$2

Motion in 1D

The motion of a particle along a straight line is described by equation x = 8 + 12t - t 3 where x is in metre and t in second. The retardation of the particle when its velocity becomes zero is

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