Question 86: Oscillations

Question

Y = A sin($$\omega$$t + $$\phi$$
0
) is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is $$Y = {A \over 2}$$ and it is moving along negative x-direction. Then the initial phase angle $$\phi$$
0
will be:

Accepted Answer

The initial phase angle $${\phi _0} = \pi  - {\pi  \over 6} = {{5\pi } \over 6}$$

Answer

$${{5\pi } \over 6}$$

Answer

$${{\pi } \over 3}$$

Answer

$${{2\pi } \over 3}$$

Answer

$${{\pi } \over 6}$$

Oscillations

Y = A sin($\omegat + \phi 0 ) is the time-displacement equation of a SHM. At t = 0 the displacement of the particle is Y = {A \over 2} and it is moving along negative x-direction. Then the initial phase angle \phi$ 0 will be:

Choose the correct answer: