Question 185: Oscillations

Question

A pendulum is suspended by a string of length 250 cm. The mass of the bob of the pendulum is 200 g. The bob is pulled aside until the string is at 60$$^\circ$$ with vertical as shown in the figure. After releasing the bob, the maximum velocity attained by the bob will be ____________ ms
$$-$$1
. (if g = 10 m/s
2
)

Accepted Answer

$${1 \over 2}m{v^2} = mgl(1 - \cos 	heta )$$
$$ \Rightarrow v = \sqrt {2gl(1 - \cos 	heta )} $$
$$ = \sqrt {2 	imes 10 	imes 2.5 	imes {1 \over 2}} $$
$$ = 5$$ m/s

Oscillations

Integer / Numeric Answer Type