Question 152: Oscillations

Question

Two particles $$A$$ and $$B$$ of equal masses are suspended from two massless springs  of spring of spring constant $${k_1}$$ and $${k_2}$$, respectively. If the maximum velocities, during oscillation, are equal, the ratio of amplitude of $$A$$ and $$B$$ is

Accepted Answer

Maximum velocity during $$SHM$$ $$ = A\omega  = A\sqrt {{k \over m}} $$
$$\left[ {\,\,} ight.$$ $$	herefore$$ $$\omega  = \sqrt {{k \over m}} $$ $$\left. {\,\,} ight]$$
Here the maximum velocity is same and $$m$$ is also same
$$	herefore$$ $${A_1}\sqrt {{k_1}}  = {A_2}\sqrt {{k_2}} $$
$$	herefore$$ $${{{A_1}} \over {{A_2}}} = \sqrt {{{{k_2}} \over {{k_1}}}} $$

Answer

$$\sqrt {{{{k_1}} \over {{k_2}}}} $$

Answer

$${{{{k_2}} \over {{k_1}}}}$$

Answer

$$\sqrt {{{{k_2}} \over {{k_1}}}} $$

Answer

$${{{{k_1}} \over {{k_2}}}}$$

Oscillations

Two particles $A and B of equal masses are suspended from two massless springs of spring of spring constant {k_1} and {k_2}, respectively. If the maximum velocities, during oscillation, are equal, the ratio of amplitude of A and B$ is

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