Question 103: Oscillations

Question

A pendulum is executing simple harmonic motion and its maximum kinetic energy is K
1
. If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K
2
. Then :

Accepted Answer

Maximum kinetic energy at lowest point B is given by
K = mg$$\ell $$ (1 $$-$$ cos $$	heta $$)
where $$	heta $$ = angular amp.
K
1
= mg$$\ell $$ (1 $$-$$ cos $$	heta $$)
K
2
= mg(2$$\ell $$) (1 $$-$$ cos $$	heta $$)
K
2
= 2K
1
.

Answer

$${K_2}$$ = $${{{K_1}} \over 2}$$

Answer

K
2
= 2K
1

Answer

K
2
= K
1

Answer

K
2
= $${{{K_1}} \over 4}$$

Oscillations

A pendulum is executing simple harmonic motion and its maximum kinetic energy is K 1 . If the length of the pendulum is doubled and it performs simple harmonic motion with the same amplitude as in the first case, its maximum kinetic energy is K 2 . Then :

Choose the correct answer: