Question 64: Oscillations

Question

Time period of a simple pendulum in a stationary lift is 'T'. If the lift accelerates with ${g \over 6}$ vertically upwards then the time period will be :
(Where g = acceleration due to gravity)

Accepted Answer

$T^{\prime}=2 \pi \sqrt{\frac{I}{g_{	ext {eff }}}}$
$T^{\prime}=2 \pi \sqrt{\frac{I}{g+\frac{g}{6}}}=2 \pi \sqrt{\frac{6 l}{7 g}}$
$\Rightarrow T^{\prime}=\sqrt{\frac{6}{7}} T$

Answer

$\sqrt {{6 \over 5}} T$

Answer

$\sqrt {{5 \over 6}} T$

Answer

$\sqrt {{6 \over 7}} T$

Answer

$\sqrt {{7 \over 6}} T$

Oscillations

Time period of a simple pendulum in a stationary lift is 'T'. If the lift accelerates with {g \over 6} vertically upwards then the time period will be : (Where g = acceleration due to gravity)

Choose the correct answer: