Question 64: Properties of Matter

Question

Given below are two statements :
Statement I : When speed of liquid is zero everywhere, pressure difference at any two points depends on equation $$\mathrm{P}_1-\mathrm{P}_2=\rho g\left(\mathrm{~h}_2-\mathrm{h}_1\right)$$.
Statement II : In ventury tube shown $$2 \mathrm{gh}=v_1^2-v_2^2$$
In the light of the above statements, choose the most appropriate answer from the options given below.

Accepted Answer

If speed $$=0$$
Then $$P_1+ho g h_1=P_2+ho g h_2$$
In given ventury tube,
$$\begin{aligned}
& \qquad P_1+ho g h+\frac{1}{2} ho v_1^2=P_2+\frac{1}{2} ho v_2^2 \
& \Rightarrow \frac{1}{2} ho\left(v_1^2-v_2^2ight)=\left(P_2-P_1ight)-ho g h \
& \Rightarrow v_1^2-v_2^2=\frac{2\left(P_2-P_1ight)}{ho}-2 g h
\end{aligned}$$

Answer

Statement I is correct but Statement II is incorrect.

Answer

Both Statement I and Statement II are correct.

Answer

Both Statement I and Statement II are incorrect.

Answer

Statement I is incorrect but Statement II is correct.

Properties of Matter

Choose the correct answer: