Question 312: Properties of Matter

Question

A stone of mass 20 g is projected from a rubber catapult of length 0.1 m and area of cross section 10
$$-$$6
m
2
stretched by an amount 0.04 m. The velocity of the projected stone is ______________ m/s.
(Young's modulus of rubber = 0.5 $$	imes$$ 10
9
N/m
2
)

Accepted Answer

By energy conservation
$${1 \over 2}.{{YA} \over L}.{x^2} = {1 \over 2}m{v^2}$$
$${{0.5 	imes {{10}^9} 	imes {{10}^{ - 6}} 	imes {{(0.04)}^2}} \over {0.1}} = {{20} \over {1000}}{v^2}$$
$$	herefore$$ $${v^2} = 400$$
$$v = 20$$ m/s

Properties of Matter

A stone of mass 20 g is projected from a rubber catapult of length 0.1 m and area of cross section 10 $-6 m 2 stretched by an amount 0.04 m. The velocity of the projected stone is ______________ m/s. (Young's modulus of rubber = 0.5 \times$ 10 9 N/m 2 )

Integer / Numeric Answer Type