Question 248: Ray Optics

Question

A ray of light is incident from air on a glass plate having thickness $$\sqrt3$$ cm and refractive index $$\sqrt2$$. The angle of incidence of a ray is equal to the critical angle for glass-air interface. The lateral displacement of the ray when it passes through the plate is ____________ $$	imes$$ 10$$^{-2}$$ cm. (given $$\sin 15^\circ  = 0.26$$)

Accepted Answer

$\sin i=\frac{1}{\sqrt{2}}=45^{\circ}$
$\Rightarrow$ at point (1)
$\mu \sin r=\sin i=\frac{1}{\sqrt{2}}$
$\sin r=\frac{1}{2} \quad \Rightarrow \quad r=30^{\circ}$
Lateral displacement
$=\frac{t}{\cos r} \sin \left(15^{\circ}ight)=\frac{\sqrt{3}}{\left(\frac{\sqrt{3}}{2}ight)} 	imes 0.26$
$=2 	imes 0.26$
$=0.52 \mathrm{~cm}$

$=52 	imes 10^{-2} \mathrm{~cm}$

Ray Optics

Integer / Numeric Answer Type