Question 116: Ray Optics

Question

Consider a light ray travelling in air is incident into a medium of refractive index $$\sqrt{2n}$$. The incident angle is twice that of refracting angle. Then, the angle of incidence will be :

Accepted Answer

According to the law,
$$1 	imes \sin 	heta  = \sqrt {2n}  	imes \sin \left( {{	heta  \over 2}} ight)$$
$$ \Rightarrow \cos {	heta  \over 2} = \sqrt {{n \over 2}} $$
$$ \Rightarrow 	heta  = 2{\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } ight)$$

Answer

$${\sin ^{ - 1}}\left( {\sqrt n } \right)$$

Answer

$${\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)$$

Answer

$${\sin ^{ - 1}}\left( {\sqrt {2n} } \right)$$

Answer

$$2{\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)$$

Ray Optics

Consider a light ray travelling in air is incident into a medium of refractive index $\sqrt{2n}$. The incident angle is twice that of refracting angle. Then, the angle of incidence will be :

Choose the correct answer: