Question 306: Thermodynamics & KTG

Question

An electric appliance supplies 6000 J/min heat to the system. If the system delivers a power of 90W. How long it would take to increase the internal energy by 2.5 $$	imes$$ 10
3
J ?

Accepted Answer

$$\Delta$$Q = $$\Delta$$U + $$\Delta$$W
$${{\Delta Q} \over {\Delta t}} = {{\Delta U} \over {\Delta t}} + {{\Delta W} \over {\Delta t}}$$
$${{6000} \over {60}}{J \over {\sec }} = {{2.5 	imes {{10}^3}} \over {\Delta t}} + 90$$
$$\Delta$$t = 250 sec

Answer

2.5 $$	imes$$ 10
2
s

Answer

4.1 $$	imes$$ 10
1
s

Answer

2.4 $$	imes$$ 10
3
s

Answer

2.5 $$	imes$$ 10
1
s

Thermodynamics & KTG

An electric appliance supplies 6000 J/min heat to the system. If the system delivers a power of 90W. How long it would take to increase the internal energy by 2.5 $\times$ 10 3 J ?

Choose the correct answer: