Question 544: Thermodynamics & KTG

Question

0.056 kg of Nitrogen is enclosed in a vessel at a temperature of 127$$^\circ$$C. Th amount of heat required to double the speed of its molecules is ____________ k cal.
Take R = 2 cal mole
$$-$$1
K
$$-$$1
)

Accepted Answer

Because the vessel is closed, it will be an isochoric process.
To double the speed, temperature must be 4 times (v $$\alpha$$$$\sqrt{T}$$)
So, T
f
= 1600 K, T
i
= 400 K
number of moles are $${{56} \over {28}} = 2$$
so Q = nCv $$\Delta$$T = 2 $$	imes$$ $${5 \over 2}$$ $$	imes$$ 2 $$	imes$$ 1200
= 12000 cal = 12 K cal

Thermodynamics & KTG

0.056 kg of Nitrogen is enclosed in a vessel at a temperature of 127$^\circC. Th amount of heat required to double the speed of its molecules is ____________ k cal. Take R = 2 cal mole -1 K -$1 )

Integer / Numeric Answer Type