Question 880: Thermodynamics & KTG

Question

A black body has maximum wavelength '$\lambda_{\mathrm{m}}$' at temperature $2000 \mathrm{~K}$. Its corresponding wavelength at temperature $3000 \mathrm{~K}$ will be

Accepted Answer

By Wien's displacement law $\lambda T=$ constant
$\begin{aligned}
& 	herefore \lambda \propto \frac{1}{\mathrm{~T}} \
& 	herefore \frac{\lambda_2}{\lambda_1}=\frac{\mathrm{T}_1}{\mathrm{~T}_1}=\frac{2000}{3000}=\frac{2}{3} \
& 	herefore \lambda_2=\frac{2}{3} \lambda_1
\end{aligned}$

Answer

$\frac{4 \lambda_m}{9}$

Answer

$\frac{2 \lambda_m}{3}$

Answer

$\frac{3 \lambda_{\mathrm{m}}}{2}$

Answer

$\frac{9}{4} \lambda_{\mathrm{m}}$

Thermodynamics & KTG

A black body has maximum wavelength '\lambda_{\mathrm{m}}' at temperature 2000 \mathrm{~K}. Its corresponding wavelength at temperature 3000 \mathrm{~K} will be

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