Question 319: Thermodynamics & KTG

Question

Consider a mixture of gas molecule of types A, B and C having masses m
A
< m
B
< m
C
. The ratio of their root mean square speeds at normal temperature and pressure is :

Accepted Answer

rms velocity of gas molecules is given as
$${v_{rms}} = \sqrt {{{3RT} \over m}} $$ ..... (i)
where, m = molar mass of the gas in kilograms per mole,
R = molar gas constant,
and T = temperature in kelvin.
According to question,
m
A
 v
B
> v
C
or $${1 \over {{v_A}}} < {1 \over {{v_B}}} < {1 \over {{v_C}}}$$

Answer

$${v_A} = {v_B} 
e {v_C}$$

Answer

$${1 \over {{v_A}}} > {1 \over {{v_B}}} > {1 \over {{v_C}}}$$

Answer

$${1 \over {{v_A}}} < {1 \over {{v_B}}} < {1 \over {{v_C}}}$$

Answer

$${v_A} = {v_B} = {v_C} = 0$$

Thermodynamics & KTG

Consider a mixture of gas molecule of types A, B and C having masses m A < m B < m C . The ratio of their root mean square speeds at normal temperature and pressure is :

Choose the correct answer: