Question 272: Thermodynamics & KTG

Question

At what temperature a gold ring of diameter 6.230 cm be heated so that it can be fitted on a wooden bangle of diameter 6.241 cm ? Both the diameters have been measured at room temperature (27$$^\circ$$C).
(Given : coefficient of linear thermal expansion of gold $$\alpha$$
L
= 1.4 $$	imes$$ 10
$$-$$5
K
$$-$$1
)

Accepted Answer

$$\Delta D = D\alpha \Delta T$$
$$\Delta T = {{0.011} \over {6.230 	imes 1.4 	imes {{10}^{ - 5}}}}$$
= 126.11$$^\circ$$C
$$\Rightarrow$$ T
f
= T + $$\Delta$$T
= (27 + 126.11)$$^\circ$$C
= 153.11$$^\circ$$C

Answer

125.7$$^\circ$$C

Answer

91.7$$^\circ$$C

Answer

425.7$$^\circ$$C

Answer

152.7$$^\circ$$C

Thermodynamics & KTG

At what temperature a gold ring of diameter 6.230 cm be heated so that it can be fitted on a wooden bangle of diameter 6.241 cm ? Both the diameters have been measured at room temperature (27$^\circC). (Given : coefficient of linear thermal expansion of gold \alpha L = 1.4 \times 10 -5 K -$1 )

Choose the correct answer: