Question 761: Thermodynamics & KTG

Question

At constant temperature, increasing the pressure of a gas by $$5 \%$$ its volume will decrease by

Accepted Answer

According to ideal gas law at constant temperature, $$\mathrm{P} \propto \frac{1}{\mathrm{~V}}$$
$$\begin{aligned}
	herefore \quad \mathrm{P}_1 \mathrm{~V}_1 & =\mathrm{P}_2 \mathrm{~V}_2 \
\mathrm{P}_1 & =\mathrm{P} \
\mathrm{P}_2 & =\mathrm{P}+\frac{5}{100} \mathrm{P}=1.05 \mathrm{P}
\end{aligned}$$
Substituting the values
$$\begin{array}{ll} 
& \mathrm{PV}_1=1.05 \mathrm{PV}_2 \
	herefore \quad & \frac{\mathrm{V}_2}{\mathrm{~V}_1}=\frac{1}{1.05} \
	herefore \quad & \frac{\mathrm{V}_2-\mathrm{V}_1}{\mathrm{~V}_1} 	imes 100=\frac{1-1.05}{1.05} 	imes 100 \
	herefore \quad & \frac{\Delta \mathrm{V}}{\mathrm{V}_1}=-4.76 \% \approx-4.7 \%
\end{array}$$
The negative sign indicates that the volume is decreasing.

Answer

$$5 \%$$

Answer

$$5.26 \%$$

Answer

$$4.20 \%$$

Answer

$$4.70 \%$$

Thermodynamics & KTG

At constant temperature, increasing the pressure of a gas by $5 \%$ its volume will decrease by

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