Question 364: Thermodynamics & KTG

Question

When the temperature of a metal wire is
increased from 0
o
C to 10
o
C, its length
increases by 0.02%. The percentage change in
its mass density will be closest to :

Accepted Answer

Given, $${{\Delta L} \over L}$$ = 0.02%
We know, $$\Delta $$L = L$$\alpha $$$$\Delta $$T
$$ \Rightarrow $$ $${{\Delta L} \over L} = \alpha \Delta T$$ = 0.02
Also, $$\beta $$ = 2$$\alpha $$
$$ \Rightarrow $$ $$\beta \Delta T = 2\alpha \Delta T$$ = 0.04
Density($$\rho $$) = $${M \over {AL}}$$
$$ \Rightarrow $$ $${{\Delta \rho } \over \rho } = {{\Delta M} \over M} - {{\Delta A} \over A} - {{\Delta L} \over L}$$ ( $${{\Delta M} \over M}$$ = 0 as M = constant)
$$ \Rightarrow $$ $${{\Delta \rho } \over \rho } = {{\Delta A} \over A} + {{\Delta L} \over L}$$
= $$\beta \Delta T + \alpha \Delta T$$
= 0.04 + 0.02 = 0.06 %

Answer

0.008

Answer

0.06

Answer

0.8

Answer

2.3

Thermodynamics & KTG

When the temperature of a metal wire is increased from 0 o C to 10 o C, its length increases by 0.02%. The percentage change in its mass density will be closest to :

Choose the correct answer: