Question 784: Thermodynamics & KTG

Question

For polyatomic gases, the ratio of molar specific heat at constant pressure to constant volume is ( $\mathrm{f}=$ degrees of freedom)

Accepted Answer

For polyatomic gases, molar-specific heat at constant volume is $\mathrm{C}_{\mathrm{V}}=(3+\mathrm{f}) \mathrm{R}$ and Molar-specific heat at constant pressure is $C_P=(4+f) R$
$	herefore \quad \frac{\mathrm{C}_{\mathrm{p}}}{\mathrm{C}_{\mathrm{V}}}=\frac{4+\mathrm{f}}{3+\mathrm{f}}$

Answer

$\frac{2+\mathrm{f}}{3+\mathrm{f}}$

Answer

$\frac{3+\mathrm{f}}{2+\mathrm{f}}$

Answer

$\frac{3+\mathrm{f}}{4+\mathrm{f}}$

Answer

$\frac{4+\mathrm{f}}{3+\mathrm{f}}$

Thermodynamics & KTG

For polyatomic gases, the ratio of molar specific heat at constant pressure to constant volume is ( \mathrm{f}= degrees of freedom)

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