Question 938: Thermodynamics & KTG

Question

The volume (V) of a monatomic
gas varies with its temperature
(T), as shown in the graph. The
ratio of work done by the gas,
to the heat absorbed by it, when
it undergoes a change from state
A to state B, is

Accepted Answer

Gas is monatomic, so C
p
= $${5 \over 2}R$$
Given process is isobaric.
$$ 	herefore $$ dQ = nC
p
dT
or dQ = n$$\left( {{5 \over 2}R} ight)$$dT
Also, dW = PdV = nRdT ($$ \because $$ PV = nRT)
$$ 	herefore $$ Required ratio = $${{dW} \over {dQ}}$$ = $${{nRdT} \over {n\left( {{5 \over 2}R} ight)dT}}$$ = $${2 \over 5}$$

Answer

$${2 \over 5}$$

Answer

$${2 \over 3}$$

Answer

$${1 \over 3}$$

Answer

$${2 \over 7}$$

Thermodynamics & KTG

The volume (V) of a monatomic gas varies with its temperature (T), as shown in the graph. The ratio of work done by the gas, to the heat absorbed by it, when it undergoes a change from state A to state B, is

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