Question 434: Thermodynamics & KTG

Question

In an experiment, a sphere of aluminium of mass 0.20 kg is heated upto 150
o
C. Immediately, it is put into water of volume 150 cc at 27
o
C kept in a calorimeter of water equivalent to 0.025 kg. Final temperature of the system is 40
o
C. The specific heat of aluminium is : (take 4.2 Joule = 1 calorie)

Accepted Answer

Let specific heat of aluminium = S,
As we know from principle of calorimetry,
Q
given
= Q
used
$$	herefore\,\,\,$$ 0.2 $$ 	imes $$ S $$ 	imes $$ (150 $$-$$ 40) =
150 $$ 	imes $$ 1 $$ 	imes $$ (40 $$-$$ 27) + 25 $$ 	imes $$ (40$$-$$27)
$$ \Rightarrow $$$$\,\,\,$$ 0.2 $$ 	imes $$ S $$ 	imes $$ 110 = 150 $$ 	imes $$ 13 + 25 $$ 	imes $$ 13
$$ \Rightarrow $$$$\,\,\,$$ S = 434 J/kg -
o
C

Answer

378 J/kg $$-$$
o
C

Answer

315 J/kg $$-$$
o
C

Answer

476 J/kg $$-$$
o
C

Answer

434 J/kg $$-$$
o
C

Thermodynamics & KTG

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