Question 14: Thermodynamics & KTG

Question

One mole of an ideal diatomic gas undergoes
transition from A to B along a path AB as
shown below.
The change in internal energy of the gas
during the transition is
![](https://app-content.cdn.examgoal.net/fly/@width/image/jaoe38c1m59ea1so/05c68367-cef0-41d4-b4c1-7d3b74d2719a/61a00180-c5c5-11ef-9ad1-6d283e3c94c4/file-jaoe38c1m59ea1sp.png?format=png)

Accepted Answer

According to the figure
The change in internal energy of the gas
$\begin{aligned}
\Delta U & =\frac{p_2 V_2-p_1 V_1}{\gamma-1} \
p_1 & =2 p a \
p_2 & =5 p a \
V_1 & =4 \mathrm{~m}^3 \
V_2 & =6 \mathrm{~m}^3 \
& =\frac{2 	imes 6-4 	imes 5}{\frac{7}{5}-1} \
& =-20 \mathrm{~kJ}
\end{aligned}$

Answer

20 kJ

Answer

$-$12 kJ

Answer

$-$20 kJ

Answer

20 J

Thermodynamics & KTG

One mole of an ideal diatomic gas undergoes transition from A to B along a path AB as shown below. The change in internal energy of the gas during the transition is

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