Question 893: Thermodynamics & KTG

Question

On an imaginary linear scale of temperature (called 'W' scale) the freezing and boiling points of water are 39$^\circ$ W and 239$^\circ$ W respectively. The temperature on the new scale corresponding to 39$^\circ$C temperature on Celsius scale will be

Accepted Answer

In Celsius scale the freezing and boiling points are 0$^\circ$C and 100$^\circ$C. In the given imaginary scale the freezing and boiling points are 39$^\circ$ W and 239$^\circ$ W. Hnece we can write
$\mathrm{\frac{C}{100}=\frac{W-39}{200}}$
For C = 39$^\circ$, $\frac{39}{100}=\mathrm{\frac{W-39}{200}}$
Solving, W = 117$^\circ$C

Answer

139$^\circ$ W

Answer

78$^\circ$ W

Answer

117$^\circ$ W

Answer

200$^\circ$ W

Thermodynamics & KTG

On an imaginary linear scale of temperature (called 'W' scale) the freezing and boiling points of water are 39^\circ W and 239^\circ W respectively. The temperature on the new scale corresponding to 39^\circC temperature on Celsius scale will be

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