Question 221: Units , Dimensions and Error Analysis

Question

In a vernier callipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be _________ $$	imes$$ 10
$$-$$2
mm.

Accepted Answer

1 MSD = $${1 \over {20}}$$ cm
$$\because$$ 10 VSD = 9 MSD
1 VSD = $${9 \over {10}}$$ $$	imes$$ $${1 \over {20}}$$ cm = $${9 \over {200}}$$ $$	imes$$ 10 mm = 0.45 mm
Now, 1 MSD = $${1 \over {20}}$$ $$	imes$$ 10 mm = 0.50 mm
LC = (0.50 $$-$$ 0.45) mm = 0.05 mm
= 5 $$	imes$$ 10
$$-$$2
mm

Units , Dimensions and Error Analysis

In a vernier callipers, each cm on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier constant will be _________ $\times 10 -$2 mm.

Integer / Numeric Answer Type