Question 158: Units , Dimensions and Error Analysis

Question

Using screw gauge of pitch 0.1 cm and
50 divisions on its circular scale, the thickness
of an object is measured. It should correctly be
recorded as

Accepted Answer

Using a screw gauge of pitch 0.1 cm and 50 divisions on its circular scale, the thickness of an object is measured as:
Measurement = (Main scale reading) + (Circular scale reading ÃÂ Least count)
where the least count is calculated as the pitch of the screw gauge divided by the number of divisions on the circular scale:
Least count = (Pitch of screw gauge) / (Number of circular scale divisions)
Least count = $${{0.1} \over {50}}$$ = 0.002 cm
Now if we multiply division of circular scale with least count then we get 0
th
digit of fraction part even.
Here only option B has 0
th
digit of fraction part even.

Answer

2.123 cm

Answer

2.124 cm

Answer

2.125 cm

Answer

2.121 cm

Units , Dimensions and Error Analysis

Using screw gauge of pitch 0.1 cm and 50 divisions on its circular scale, the thickness of an object is measured. It should correctly be recorded as

Choose the correct answer: