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Back to Units , Dimensions and Error Analysis
Class 11 • Physics • Chapter-1
Units , Dimensions and Error Analysis
Question 15 of 230
15
Medium
JEE Mains
2026
The dimensional formula of
\frac{1}{2} \epsilon_0 E^2
(
\epsilon_0
= permittivity of vacuum and
E
= electric field) is
M^a L^b T^c
. The value of
2a - b + c =
________.
Choose the correct answer:
A
0
B
1
C
-1
D
2
Select an answer first
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