Question 184: Units , Dimensions and Error Analysis

Question

Dimensional formula for thermal conductivity is (here K denotes the temperature):

Accepted Answer

$ 	herefore $ ${{d	heta } \over {dt}} = kA{{dT} \over {dx}}$
$ \Rightarrow $ k = ${{\left( {{{d	heta } \over {dt}}} ight)} \over {A\left( {{{dT} \over {dx}}} ight)}}$
$ \Rightarrow $ [k] = ${{\left[ {M{L^2}{T^{ - 3}}} ight]} \over {\left[ {{L^2}} ight]\left[ {K{L^{ - 1}}} ight]}}$
= [MLT
Ã¢ÂÂ3
K
Ã¢ÂÂ1
]

Answer

MLT
–3
K
–1

Answer

MLT
–2
K
–2

Answer

MLT
–2
K

Answer

MLT
–3
K

Units , Dimensions and Error Analysis

Dimensional formula for thermal conductivity is (here K denotes the temperature):

Choose the correct answer: