Question 149: Units , Dimensions and Error Analysis

Question

The dimension of mutual inductance is :

Accepted Answer

$\because$ $U = {1 \over 2}M{i^2}$
$ \Rightarrow [M] = {{[U]} \over {[{i^2}]}} = {{M{L^2}{T^{ - 2}}} \over {{A^2}}}$
$ = [M{L^2}{T^{ - 2}}{A^{ - 2}}]$

Answer

$[M{L^2}{T^{ - 2}}{A^{ - 1}}]$

Answer

$[M{L^2}{T^{ - 3}}{A^{ - 1}}]$

Answer

$[M{L^2}{T^{ - 2}}{A^{ - 2}}]$

Answer

$[M{L^2}{T^{ - 3}}{A^{ - 2}}]$

Units , Dimensions and Error Analysis

The dimension of mutual inductance is :

Choose the correct answer: