Question 236: Units , Dimensions and Error Analysis

Question

Dimensions of ${1 \over {{\mu _0}{\varepsilon _0}}}$, where symbols have their usual meaning, are

Accepted Answer

The velocity of light in vacuum is
c = ${1 \over {\sqrt {{\mu _0}{\varepsilon _0}} }}$;
$	herefore[{1 \over {{\mu _0}{\varepsilon _0}}}]$ = [c
2
] = [L
2
T
-2
]
$	herefore$ Dimension of ${1 \over {{\mu _0}{\varepsilon _0}}}$ = [L
2
T
-2
]

Answer

[ L
-1
T ]

Answer

[ L
-2
T
2
]

Answer

[ L
2
T
-2
]

Answer

[ LT
-1
]

Units , Dimensions and Error Analysis

Dimensions of {1 \over {{\mu _0}{\varepsilon _0}}}, where symbols have their usual meaning, are

Choose the correct answer: