Question 192: Units , Dimensions and Error Analysis

Question

In the following ‘I’ refers to current and other symbols have their usual meaning.
Choose the option that corresponds to the
dimensions of electrical conductivity :

Accepted Answer

We know. resistivity ($$ho $$) = $${{RA} \over L}$$
and conductivity = $${1 \over ho }$$ = $${1 \over {RA}}$$
As   R = $${V \over {m I}}$$
$$ 	herefore $$   conductivity = $${{L{m I}} \over {VA}}$$
Also  V = $${\omega  \over q}$$ = $${\omega  \over {it}}$$ = $${{\left[ {M{L^2}{T^{ - 2}}} ight]} \over {\left[ {m I} ight]\left[ T ight]}}$$ = $$\left[ {M{L^2}{T^{ - 3}}{{m I}^{ - 1}}} ight]$$
$$ 	herefore $$   Conductivity = $${{\left[ {m{L}} ight]\left[ {m I} ight]} \over {\left[ {M{L^2}{T^{ - 3}}{{m{I}}^{ - 1}}} ight]\left[ {{L^2}} ight]}}$$
=   $$\left[ {{M^{ - 1}}{L^{ - 3}}{T^3}{{m I}^2}} ight]$$

Answer

ML
$$-$$3
T
$$-$$3
I2

Answer

M
$$-$$1
L
3
T
3
I

Answer

M
$$-$$1
L
$$-$$3
T
3
I
2

Answer

M
$$-$$1
L
$$-$$3
T
3
I

Units , Dimensions and Error Analysis

In the following ‘I’ refers to current and other symbols have their usual meaning. Choose the option that corresponds to the dimensions of electrical conductivity :

Choose the correct answer: