Question 138: Units , Dimensions and Error Analysis

Question

The dimensions of $\left(\frac{\mathrm{B}^{2}}{\mu_{0}}\right)$ will be :
(if $\mu_{0}$ : permeability of free space and $B$ : magnetic field)

Accepted Answer

$\left[ {{{{B^2}} \over {{\mu _0}}}} \right]=$ [Energy density]
$ = {{M{L^2}{T^{ - 2}}} \over {{L^3}}} = M{L^{ - 1}}{T^{ - 2}}$

Answer

$\left[\mathrm{M}\, \mathrm{L}^2 \,\mathrm{T}^{-2}\right]$

Answer

$\left[\mathrm{M} \,\mathrm{L} \,\mathrm{T}^{-2}\right]$

Answer

$\left[\mathrm{M} \,\mathrm{L}^{-1} \,\mathrm{~T}^{-2}\right]$

Answer

$\left[\mathrm{M} \,\mathrm{L}^{2} \mathrm{~T}^{-2} \mathrm{~A}^{-1}\right]$

Units , Dimensions and Error Analysis