Question 103: Wave Optics

Question

In Young's double slit experiment, the fringe width is $$12 \mathrm{~mm}$$. If the entire arrangement is placed in water of refractive index $$\frac{4}{3}$$, then the fringe width becomes (in mm):

Accepted Answer

$$B = 12 	imes {10^{ - 3}}$$
$$\beta ' = {\beta  \over \mu } = {{12 	imes {{10}^{ - 3}}} \over {{4 \over 3}}}$$
$$ = 9 	imes {10^{ - 3}}$$ m = 9 mm

Answer

16

Answer

9

Answer

48

Answer

12

Wave Optics

In Young's double slit experiment, the fringe width is $12 \mathrm{~mm}. If the entire arrangement is placed in water of refractive index \frac{4}{3}$, then the fringe width becomes (in mm):

Choose the correct answer: