Question 366: Waves

Question

Two waves are superimposed whose ratio of intensities is $$9: 1$$. The ratio of maximum and minimum intensity is

Accepted Answer

$$	ext { Given: } \frac{\mathrm{I}_1}{\mathrm{I}_2}=\frac{9}{1}=\frac{\mathrm{a}_1^2}{\mathrm{a}_2^2} \quad 	herefore \frac{\mathrm{a}_1}{\mathrm{a}_2}=\frac{3}{1}$$
$$\begin{aligned}
& 	herefore \mathrm{a}_1=3 \mathrm{a}_2 \
& 	herefore \frac{I_{	ext {max }}}{I_{	ext {min }}}=\frac{\left(a_1+a_2ight)^2}{\left(a_1-a_2ight)^2}=\frac{\left(3 a_2+a_2ight)^2}{\left(3 a_2-a_2ight)^2} \
& =\frac{4^2}{2^2}=\frac{16}{4}=4: 1 \
&
\end{aligned}$$

Answer

$$9: 1$$

Answer

$$4: 1$$

Answer

$$3: 1$$

Answer

$$5: 3$$

Waves

Two waves are superimposed whose ratio of intensities is $9: 1$. The ratio of maximum and minimum intensity is

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