Question 209: Waves

Question

Two tuning forks of frequencies 256 Hz and 258 Hz are sounded together. The time interval between two consecutive maxima is

Accepted Answer

Step 1: Calculate beat frequency
$ f_{	ext{beat}} = |f_2 - f_1| = |258 - 256| = 2 \,	ext{Hz} $
Step 2: Time interval between two consecutive maxima
The time between beats (successive maxima) is the reciprocal of beat frequency:
$ T_{	ext{beat}} = \frac{1}{f_{	ext{beat}}} = \frac{1}{2} = 0.5 \,	ext{s} $
Ã¢ÂÂ Final Answer:
$ \boxed{0.5 \,	ext{s} 	ext{ (Option D)}} $

Answer

250 s

Answer

252 s

Answer

2 s

Answer

0.5 s

Waves

Two tuning forks of frequencies 256 Hz and 258 Hz are sounded together. The time interval between two consecutive maxima is

Choose the correct answer: