Question 210: Work, Energy and Power & Circular Motion

Question

A body of mass $' m ',$ acceleration uniformly from rest to $'{v_1}'$ in time ${T}$. The instantaneous power delivered to the body as a function of time is given by

Accepted Answer

Assume acceleration of body be $a$
$	herefore$ ${v_1} = 0 + a{T} \Rightarrow a = {{{v_1}} \over {{T}}}$
$	herefore$ $v = at \Rightarrow v = {{{v_1}t} \over {{T}}}$
${P_{inst}} = \overrightarrow F .\overrightarrow v  = \left( {m\overrightarrow a } ight).\overrightarrow v $
$= \left( {{{m{v_1}} \over {{T}}}} ight)\left( {{{{v_1}t} \over {{T}}}} ight)$
$ = m{\left( {{{{v_1}} \over {{T}}}} ight)^2}t$

Answer

${{m{v_1}{t^2}} \over {{T}}}$

Answer

${{mv_1^2t} \over {T^2}}$

Answer

${{m{v_1}t} \over {{T}}}$

Answer

${{mv_1^2t} \over {{T}}}$

Work, Energy and Power & Circular Motion

A body of mass ' m ', acceleration uniformly from rest to '{v_1}' in time {T}. The instantaneous power delivered to the body as a function of time is given by

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