Question 125: Work, Energy and Power & Circular Motion

Question

A constant power delivering machine has towed a box, which was initially at rest, along a horizontal straight line. The distance moved by the box in time 't' is proportional to :-

Accepted Answer

$$P = F.v = mav$$
$$P = {{mvdv} \over {dt}}$$
$$\int\limits_0^t {Pdt}  = m\int\limits_0^v {vdv} $$
$$Pt = {{m{v^2}} \over 2}$$
$$v = \sqrt {{{2Pt} \over m}} $$
$${{dx} \over {dt}} = \sqrt {{{2Pt} \over m}} $$
$$\int {dx}  = \int {\sqrt {{{2Pt} \over m}} } dt$$
$$x \propto {t^{3/2}}$$

Answer

t
2/3

Answer

t
3/2

Answer

t

Answer

t
1/2

Work, Energy and Power & Circular Motion

A constant power delivering machine has towed a box, which was initially at rest, along a horizontal straight line. The distance moved by the box in time 't' is proportional to :-

Choose the correct answer: