Question 320: Work, Energy and Power & Circular Motion

Question

In U.C.M., when time interval $\delta t \rightarrow 0$, the angle between change in velocity ( $\delta \mathbf{v}$ ) and linear velocity $(\boldsymbol{v})$ will be

Accepted Answer

The direction of change in velocity $(\delta \mathbf{v}$ ) is given by
$$\phi=\frac{180^{\circ}-	heta}{2}=90^{\circ}-\frac{	heta}{2}\quad	ext{.... (i)}$$
This can be shown graphically as
For small time interval, i.e., $\delta t ightarrow 0$, then angle between $v_1$ and $v_2$ is very small i.e., $	heta \approx 0^{\circ}$.
So, from Eq. (i), we get
$$\phi=90^{\circ}$$

Answer

$0^\circ$

Answer

$90^\circ$

Answer

$180^\circ$

Answer

$45^\circ$

Work, Energy and Power & Circular Motion

In U.C.M., when time interval \delta t \rightarrow 0, the angle between change in velocity ( \delta \mathbf{v} ) and linear velocity (\boldsymbol{v}) will be

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