Work, Energy and Power & Circular Motion

A block of mass $1 \mathrm{~kg} is pushed up a surface inclined to horizontal at an angle of 60^{\circ} by a force of 10 \mathrm{~N} parallel to the inclined surface as shown in figure. When the block is pushed up by 10 \mathrm{~m} along inclined surface, the work done against frictional force is : \left[g=10 \mathrm{~m} / \mathrm{s}^2\right]