Question 86: Laws of Motion

Question

A block of mass $m$ slides down the plane inclined at angle $$30^{\circ}$$ with an acceleration $$\frac{g}{4}$$. The value of coefficient of kinetic friction will be:

Accepted Answer

$\mathrm{Mg} \sin 30^{\circ}-\mu \mathrm{mg} \cos 30^{\circ}=\mathrm{ma}$
$$
\frac{g}{2}-\frac{\sqrt{3}}{2} \cdot \mu g=\frac{g}{4}
$$
$$
\begin{aligned}
& \frac{\sqrt{3}}{2} \mu=\frac{1}{4} \\
& \mu=\frac{1}{2 \sqrt{3}}
\end{aligned}
$$

Answer

$$\frac{2 \sqrt{3}-1}{2}$$

Answer

$$\frac{\sqrt{3}}{2}$$

Answer

$$\frac{1}{2 \sqrt{3}}$$

Answer

$$\frac{2 \sqrt{3}+1}{2}$$

Laws of Motion

A block of mass m slides down the plane inclined at angle $30^{\circ} with an acceleration \frac{g}{4}$. The value of coefficient of kinetic friction will be:

Choose the correct answer: