Question 137: Laws of Motion

Question

A rocket is fired vertically from the earth with an acceleration of 2g, where g is the
gravitational acceleration. On an inclined plane inside the rocket, making an angle $$	heta $$ with the horizontal, a point object of mass m is kept. The minimum coefficient of friction $$\mu $$min between the mass and the inclined surface such that the mass does not move is :

Accepted Answer

Rocket is moving upward with acceleration 2g and gravitation acceleration is g downward direction.
So, acceleration experienced by the point object,
= 2g $$-$$ ($$-$$ g) = 3g
At equilibrium,
N = 3mgcos$$	heta $$
$$\mu $$N = 3mgsin$$	heta $$
$$ \Rightarrow $$   $$\mu $$ (3mgcos$$	heta $$) = 3mg sin$$	heta $$
$$ \Rightarrow $$   $$\mu $$ = tan$$	heta $$

Answer

tan$$	heta $$

Answer

2tan$$	heta $$

Answer

3tan$$	heta $$

Answer

tan2$$	heta $$

Laws of Motion

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