Question 197: Laws of Motion

Question

Two blocks of masses 6 kg and 4 kg are placed in contact with each other on a smooth surface as shown. If a force of 5 N is applied on a heavier block, the force on the lighter block is

Accepted Answer

Given: $\mathrm{m}_1=6 \mathrm{~kg}, \mathrm{~m}_2=4 \mathrm{~kg}$ and $\mathrm{F}=5 \mathrm{~N}$ $\mathrm{F}=\left(\mathrm{m}_1+\mathrm{m}_2ight) \mathrm{a}$
$	herefore \quad a=\frac{F}{\left(m_1+m_2ight)}=\frac{5}{(6+4)}=0.5 \mathrm{~m} / \mathrm{s}^2$

$$
\begin{aligned}
	herefore \quad 	ext { Force on second mass } & =\mathrm{m}_2 	imes \mathrm{a} \
& =4 	imes 0.5 \
& =2 \mathrm{~N}
\end{aligned}$$

Answer

5N

Answer

4N

Answer

2N

Answer

1N

Laws of Motion

Two blocks of masses 6 kg and 4 kg are placed in contact with each other on a smooth surface as shown. If a force of 5 N is applied on a heavier block, the force on the lighter block is

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