Question 107: Laws of Motion

Question

A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 ms$$-$$1. The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is :
[use g = 9.8 ms$$-$$2]

Accepted Answer

$$S = {{{u^2}} \over {2a}} = {{{u^2}} \over {2(\mu g)}}$$
$$ = {{{{(9.8)}^2}} \over {2 	imes 0.5 	imes (9.8)}}$$
$$ = {{9.8} \over 1}$$
$$ = 9.8$$ m

Answer

4.9 m

Answer

9.8 m

Answer

12.5 m

Answer

19.6 m

Laws of Motion

A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 ms$-1. The coefficient of friction between the surface and block is 0.5. The distance covered by the block before coming to rest is : [use g = 9.8 ms-$2]

Choose the correct answer: