Question 233: Laws of Motion

Question

A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A bob is suspended from the roof of the car by a light wire of length 1.0 m. The  angle made by the  wire with the vertical is

Accepted Answer

Let $$	heta $$ is the angle made by the wire with
the vertical.
$$ 	herefore $$ $$	an 	heta  = {{{v^2}} \over {rg}}$$
Here, v = 10 m/s, r = 10 m, g = 10 m/s
2
$$ 	herefore $$ $$	an 	heta  = {{{{\left( {10\,\,m/s} ight)}^2}} \over {10\,m\left( {10\,\,m/{s^2}} ight)}} = 1$$
$$	heta  = {	an ^{ - 1}}\left( 1 ight) = {\pi  \over 4}$$

Answer

$${\pi  \over 3}$$

Answer

$${\pi  \over 6}$$

Answer

$${\pi  \over 4}$$

Answer

0o

Laws of Motion

A car is moving in a circular horizontal track of radius 10 m with a constant speed of 10 m/s. A bob is suspended from the roof of the car by a light wire of length 1.0 m. The angle made by the wire with the vertical is

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