Question 47: Laws of Motion

Question

A cubic block of mass $m$ is sliding down on an inclined plane at $60^{\circ}$ with an acceleration of $\frac{g}{2}$, the value of coefficient of kinetic friction is

Accepted Answer

$$\begin{aligned}
& m g \sin 60^{\circ}-\mu m g \cos 60^{\circ}=m a \
& g \sin 60-\mu g \cos 60=\frac{g}{2} \
& \frac{\sqrt{3}}{2}-\frac{\mu}{2}=\frac{1}{2} \
& \mu=\sqrt{3}-1
\end{aligned}$$

Answer

$\frac{\sqrt{3}}{2}$

Answer

$\frac{\sqrt{2}}{3}$

Answer

$1-\frac{\sqrt{3}}{2}$

Answer

$\sqrt{3}-1$

Laws of Motion

A cubic block of mass m is sliding down on an inclined plane at 60^{\circ} with an acceleration of \frac{g}{2}, the value of coefficient of kinetic friction is

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