Question 166: Laws of Motion

Question

Four forces are acting at a point $$\mathrm{P}$$ in equilibrium as shown in figure. The ratio of force $$\mathrm{F}_{1}$$ to $$\mathrm{F}_{2}$$ is $$1: x$$ where $$x=$$ _____________.

Accepted Answer

$${F_1} = \, + 2 	imes {1 \over {\sqrt 2 }} - {1 \over {\sqrt 2 }} = {1 \over {\sqrt 2 }}$$
$${F_2} = 2 	imes {1 \over {\sqrt 2 }} + {1 \over {\sqrt 2 }} = {3 \over {\sqrt 2 }}$$
$${{{F_1}} \over {{F_2}}} = {1 \over 3} = {1 \over x} \Rightarrow x = 3$$

Laws of Motion

Four forces are acting at a point $\mathrm{P} in equilibrium as shown in figure. The ratio of force \mathrm{F}_{1} to \mathrm{F}_{2} is 1: x where x=$ _____________.

Choose the correct answer: