Question 144: Laws of Motion

Question

A block is kept on a frictionless inclined surface with angle of inclination $$'\,\alpha \,'.$$ The incline is given an acceleration $$a$$ to keep the block stationary. Then $$a$$ is equal to

Accepted Answer

Acceleration of the block is to the right. Pseudo force acting on the block to the left.
From diagram we can say,
m$$a$$cos$$\alpha $$ = m$$g$$sin$$\alpha $$
$$ \Rightarrow a = g	an \alpha $$

Answer

$$g$$ $$cosec$$ $$\alpha $$

Answer

$$g/tan$$ $$\alpha $$

Answer

$$g$$ $$tan$$ $$\alpha $$

Answer

$$g$$

Laws of Motion

A block is kept on a frictionless inclined surface with angle of inclination $'\,\alpha \,'. The incline is given an acceleration a to keep the block stationary. Then a$ is equal to

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