Question 251: Laws of Motion

Question

A block of mass 10 kg placed on rough horizontal surface having coefficient of friction m = 0.5,  if a horizontal force of 100 N acting on it then acceleration of the block will be

Accepted Answer

m = 10 kg, R = mg
$$ 	herefore $$ Frictional force = f
k
= $${\mu _k}R = {\mu _k}mg$$
= 0.5 ÃÂ 10 ÃÂ 10
= 50 N [g = 10 m/sec
2
]
$$ 	herefore $$ Net force acting on the body = F = P Ã¢ÂÂ f
k
= 100 Ã¢ÂÂ 50 = 50 N.
$$ 	herefore $$ Acceleration of the block = a = F/m
= 50/10 = 5 m/sec
2
.

Answer

10 m/s2

Answer

5 m/s2

Answer

15 m/s2

Answer

0.5  m/s2.

Laws of Motion

A block of mass 10 kg placed on rough horizontal surface having coefficient of friction m = 0.5, if a horizontal force of 100 N acting on it then acceleration of the block will be

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